Base | Representation |
---|---|
bin | 111101000000011111… |
… | …1101111011111010101 |
3 | 110112011112110202100112 |
4 | 1322000333233133111 |
5 | 4121303340241432 |
6 | 140104151452405 |
7 | 12315425633354 |
oct | 1720077573725 |
9 | 415145422315 |
10 | 131013212117 |
11 | 506205a7417 |
12 | 21484087105 |
13 | c47ba89628 |
14 | 64abc9599b |
15 | 361bca47b2 |
hex | 1e80fef7d5 |
131013212117 has 2 divisors, whose sum is σ = 131013212118. Its totient is φ = 131013212116.
The previous prime is 131013212093. The next prime is 131013212131. The reversal of 131013212117 is 711212310131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124553232241 + 6459979876 = 352921^2 + 80374^2 .
It is a cyclic number.
It is not a de Polignac number, because 131013212117 - 218 = 131012949973 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131013212092 and 131013212101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131013212417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506606058 + 65506606059.
It is an arithmetic number, because the mean of its divisors is an integer number (65506606059).
Almost surely, 2131013212117 is an apocalyptic number.
It is an amenable number.
131013212117 is a deficient number, since it is larger than the sum of its proper divisors (1).
131013212117 is an equidigital number, since it uses as much as digits as its factorization.
131013212117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 131013212117 its reverse (711212310131), we get a palindrome (842225522248).
The spelling of 131013212117 in words is "one hundred thirty-one billion, thirteen million, two hundred twelve thousand, one hundred seventeen".
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