Base | Representation |
---|---|
bin | 1011111010100110010001… |
… | …0000001010110101111111 |
3 | 1201101110211100221022100211 |
4 | 2332221210100022311333 |
5 | 3204123012021304434 |
6 | 43510400253333251 |
7 | 2521353140244223 |
oct | 276514420126577 |
9 | 51343740838324 |
10 | 13101332213119 |
11 | 41a1275535277 |
12 | 1577161797227 |
13 | 7405b14a1237 |
14 | 334171d90783 |
15 | 17abe0826464 |
hex | bea6440ad7f |
13101332213119 has 2 divisors, whose sum is σ = 13101332213120. Its totient is φ = 13101332213118.
The previous prime is 13101332213083. The next prime is 13101332213131. The reversal of 13101332213119 is 91131223310131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13101332213119 is a prime.
It is a super-2 number, since 2×131013322131192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101332243119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550666106559 + 6550666106560.
It is an arithmetic number, because the mean of its divisors is an integer number (6550666106560).
Almost surely, 213101332213119 is an apocalyptic number.
13101332213119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101332213119 is an equidigital number, since it uses as much as digits as its factorization.
13101332213119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 31.
The spelling of 13101332213119 in words is "thirteen trillion, one hundred one billion, three hundred thirty-two million, two hundred thirteen thousand, one hundred nineteen".
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