13101404020153 has 2 divisors, whose sum is σ = 13101404020154. Its totient is φ = 13101404020152.

The previous prime is 13101404020129. The next prime is 13101404020157. The reversal of 13101404020153 is 35102040410131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12529561042944 + 571842977209 = 3539712^2 + 756203^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101404020153 - 2²⁵ = 13101370465721 is a prime.

It is not a weakly prime, because it can be changed into another prime (13101404020157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550702010076 + 6550702010077.

It is an arithmetic number, because the mean of its divisors is an integer number (6550702010077).

Almost surely, 2^{13101404020153} is an apocalyptic number.

It is an amenable number.

13101404020153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101404020153 is an equidigital number, since it uses as much as digits as its factorization.

13101404020153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13101404020153 its reverse (35102040410131), we get a palindrome (48203444430284).

The spelling of 13101404020153 in words is "thirteen trillion, one hundred one billion, four hundred four million, twenty thousand, one hundred fifty-three".