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1310141263 is a prime number
BaseRepresentation
bin100111000010111…
…0010101101001111
310101022021001221111
41032011302231033
510140344010023
6334000512451
744316005554
oct11605625517
93338231844
101310141263
116125a4582
1230691b727
1317b578c22
14c6000a2b
157a04500d
hex4e172b4f

1310141263 has 2 divisors, whose sum is σ = 1310141264. Its totient is φ = 1310141262.

The previous prime is 1310141233. The next prime is 1310141281. The reversal of 1310141263 is 3621410131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3621410131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310141263 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310141233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655070631 + 655070632.

It is an arithmetic number, because the mean of its divisors is an integer number (655070632).

Almost surely, 21310141263 is an apocalyptic number.

1310141263 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310141263 is an equidigital number, since it uses as much as digits as its factorization.

1310141263 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

The square root of 1310141263 is about 36195.8735631563. The cubic root of 1310141263 is about 1094.2235101636.

Adding to 1310141263 its reverse (3621410131), we get a palindrome (4931551394).

The spelling of 1310141263 in words is "one billion, three hundred ten million, one hundred forty-one thousand, two hundred sixty-three".