Base | Representation |
---|---|
bin | 10011000100001010100… |
… | …011111010100100111011 |
3 | 11122020201001201020002212 |
4 | 103010022203322210323 |
5 | 132431132401244121 |
6 | 2441512050245335 |
7 | 163440355026644 |
oct | 23041243724473 |
9 | 4566631636085 |
10 | 1310142212411 |
11 | 4656a013a51a |
12 | 191ab7b8684b |
13 | 967133b7c66 |
14 | 475a856a6cb |
15 | 2412e52525b |
hex | 1310a8fa93b |
1310142212411 has 2 divisors, whose sum is σ = 1310142212412. Its totient is φ = 1310142212410.
The previous prime is 1310142212399. The next prime is 1310142212413. The reversal of 1310142212411 is 1142122410131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310142212411 is a prime.
Together with 1310142212413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1310142212413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655071106205 + 655071106206.
It is an arithmetic number, because the mean of its divisors is an integer number (655071106206).
Almost surely, 21310142212411 is an apocalyptic number.
1310142212411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310142212411 is an equidigital number, since it uses as much as digits as its factorization.
1310142212411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1310142212411 its reverse (1142122410131), we get a palindrome (2452264622542).
The spelling of 1310142212411 in words is "one trillion, three hundred ten billion, one hundred forty-two million, two hundred twelve thousand, four hundred eleven".
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