Base | Representation |
---|---|
bin | 111101000000100001… |
… | …1101000000001110100 |
3 | 110112011121101110210210 |
4 | 1322001003220001310 |
5 | 4121304120331012 |
6 | 140104225345420 |
7 | 12315440403342 |
oct | 1720103500164 |
9 | 415147343723 |
10 | 131014230132 |
11 | 50621132255 |
12 | 21484498270 |
13 | c47c054ac6 |
14 | 64ac07c992 |
15 | 361be0623c |
hex | 1e810e8074 |
131014230132 has 12 divisors (see below), whose sum is σ = 305699870336. Its totient is φ = 43671410040.
The previous prime is 131014230077. The next prime is 131014230133. The reversal of 131014230132 is 231032410131.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 131014230099 and 131014230108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131014230133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5458926244 + ... + 5458926267.
Almost surely, 2131014230132 is an apocalyptic number.
131014230132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131014230132 is an abundant number, since it is smaller than the sum of its proper divisors (174685640204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131014230132 is a wasteful number, since it uses less digits than its factorization.
131014230132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10917852518 (or 10917852516 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 131014230132 its reverse (231032410131), we get a palindrome (362046640263).
The spelling of 131014230132 in words is "one hundred thirty-one billion, fourteen million, two hundred thirty thousand, one hundred thirty-two".
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