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13102001333 is a prime number
BaseRepresentation
bin11000011001111000…
…01010110010110101
31020211002201121222122
430030330022302311
5203313103020313
610004033205325
7642452113421
oct141474126265
936732647878
1013102001333
115613813583
122657a00845
13130a566415
148c411bb81
1551a39e708
hex30cf0acb5

13102001333 has 2 divisors, whose sum is σ = 13102001334. Its totient is φ = 13102001332.

The previous prime is 13102001329. The next prime is 13102001347. The reversal of 13102001333 is 33310020131.

13102001333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10387278724 + 2714722609 = 101918^2 + 52103^2 .

It is an emirp because it is prime and its reverse (33310020131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13102001333 - 22 = 13102001329 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102001933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551000666 + 6551000667.

It is an arithmetic number, because the mean of its divisors is an integer number (6551000667).

Almost surely, 213102001333 is an apocalyptic number.

It is an amenable number.

13102001333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102001333 is an equidigital number, since it uses as much as digits as its factorization.

13102001333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13102001333 its reverse (33310020131), we get a palindrome (46412021464).

The spelling of 13102001333 in words is "thirteen billion, one hundred two million, one thousand, three hundred thirty-three".