131020142001149 has 2 divisors, whose sum is σ = 131020142001150. Its totient is φ = 131020142001148.

The previous prime is 131020142001121. The next prime is 131020142001169. The reversal of 131020142001149 is 941100241020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92167584156025 + 38852557845124 = 9600395^2 + 6233182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131020142001149 is a prime.

It is a super-3 number, since 3×131020142001149³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020142001169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510071000574 + 65510071000575.

It is an arithmetic number, because the mean of its divisors is an integer number (65510071000575).

Almost surely, 2^{131020142001149} is an apocalyptic number.

It is an amenable number.

131020142001149 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020142001149 is an equidigital number, since it uses as much as digits as its factorization.

131020142001149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 29.

The spelling of 131020142001149 in words is "one hundred thirty-one trillion, twenty billion, one hundred forty-two million, one thousand, one hundred forty-nine".