Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1000000000011001010011 |
3 | 1201101112121110010212222021 |
4 | 2332222031120000121103 |
5 | 3204130420131231311 |
6 | 43510552540552311 |
7 | 2521406215414345 |
oct | 276521530003123 |
9 | 51345543125867 |
10 | 13102022133331 |
11 | 41a1599a1a56a |
12 | 1577314852697 |
13 | 7406913c1651 |
14 | 3341d9863295 |
15 | 17ac311a7171 |
hex | bea8d600653 |
13102022133331 has 2 divisors, whose sum is σ = 13102022133332. Its totient is φ = 13102022133330.
The previous prime is 13102022133293. The next prime is 13102022133373. The reversal of 13102022133331 is 13333122020131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13102022133331 - 213 = 13102022125139 is a prime.
It is a super-2 number, since 2×131020221333312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13102022133296 and 13102022133305.
It is not a weakly prime, because it can be changed into another prime (13102082133331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551011066665 + 6551011066666.
It is an arithmetic number, because the mean of its divisors is an integer number (6551011066666).
Almost surely, 213102022133331 is an apocalyptic number.
13102022133331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102022133331 is an equidigital number, since it uses as much as digits as its factorization.
13102022133331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13102022133331 its reverse (13333122020131), we get a palindrome (26435144153462).
The spelling of 13102022133331 in words is "thirteen trillion, one hundred two billion, twenty-two million, one hundred thirty-three thousand, three hundred thirty-one".
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