Search a number
-
+
131020224211411 is a prime number
BaseRepresentation
bin11101110010100110000101…
…111011000010100111010011
3122011220102002200212002201221
4131302212011323002213103
5114133113404344231121
61142353505435305511
736411620203341133
oct3562460573024723
9564812080762657
10131020224211411
1138824401971527
121284071bbab297
13581520080bc12
14244d5ac5b2ac3
15102320b5b8b41
hex772985ec29d3

131020224211411 has 2 divisors, whose sum is σ = 131020224211412. Its totient is φ = 131020224211410.

The previous prime is 131020224211367. The next prime is 131020224211421. The reversal of 131020224211411 is 114112422020131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131020224211411 is a prime.

It is a super-2 number, since 2×1310202242114112 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131020224211421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510112105705 + 65510112105706.

It is an arithmetic number, because the mean of its divisors is an integer number (65510112105706).

Almost surely, 2131020224211411 is an apocalyptic number.

131020224211411 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020224211411 is an equidigital number, since it uses as much as digits as its factorization.

131020224211411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 131020224211411 its reverse (114112422020131), we get a palindrome (245132646231542).

The spelling of 131020224211411 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, two hundred eleven thousand, four hundred eleven".