Base | Representation |
---|---|
bin | 11101110010100110000101… |
… | …111011000010100111010011 |
3 | 122011220102002200212002201221 |
4 | 131302212011323002213103 |
5 | 114133113404344231121 |
6 | 1142353505435305511 |
7 | 36411620203341133 |
oct | 3562460573024723 |
9 | 564812080762657 |
10 | 131020224211411 |
11 | 38824401971527 |
12 | 1284071bbab297 |
13 | 581520080bc12 |
14 | 244d5ac5b2ac3 |
15 | 102320b5b8b41 |
hex | 772985ec29d3 |
131020224211411 has 2 divisors, whose sum is σ = 131020224211412. Its totient is φ = 131020224211410.
The previous prime is 131020224211367. The next prime is 131020224211421. The reversal of 131020224211411 is 114112422020131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131020224211411 is a prime.
It is a super-2 number, since 2×1310202242114112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131020224211421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510112105705 + 65510112105706.
It is an arithmetic number, because the mean of its divisors is an integer number (65510112105706).
Almost surely, 2131020224211411 is an apocalyptic number.
131020224211411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020224211411 is an equidigital number, since it uses as much as digits as its factorization.
131020224211411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 131020224211411 its reverse (114112422020131), we get a palindrome (245132646231542).
The spelling of 131020224211411 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, two hundred eleven thousand, four hundred eleven".
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