131020224411437 has 2 divisors, whose sum is σ = 131020224411438. Its totient is φ = 131020224411436.

The previous prime is 131020224411389. The next prime is 131020224411467. The reversal of 131020224411437 is 734114422020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120649596051721 + 10370628359716 = 10984061^2 + 3220346^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131020224411437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131020224411397 and 131020224411406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020224411467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510112205718 + 65510112205719.

It is an arithmetic number, because the mean of its divisors is an integer number (65510112205719).

Almost surely, 2^{131020224411437} is an apocalyptic number.

It is an amenable number.

131020224411437 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020224411437 is an equidigital number, since it uses as much as digits as its factorization.

131020224411437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 35.

Adding to 131020224411437 its reverse (734114422020131), we get a palindrome (865134646431568).

The spelling of 131020224411437 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, four hundred eleven thousand, four hundred thirty-seven".