Base | Representation |
---|---|
bin | 10011000100001110001… |
… | …001001011001001011101 |
3 | 11122020212020210120020012 |
4 | 103010032021023021131 |
5 | 132431243242430021 |
6 | 2441522034333005 |
7 | 163442014615154 |
oct | 23041611131135 |
9 | 4566766716205 |
10 | 1310202311261 |
11 | 465721058698 |
12 | 191b1412a165 |
13 | 9672299abcc |
14 | 475b253259b |
15 | 2413494735b |
hex | 1310e24b25d |
1310202311261 has 2 divisors, whose sum is σ = 1310202311262. Its totient is φ = 1310202311260.
The previous prime is 1310202311183. The next prime is 1310202311273. The reversal of 1310202311261 is 1621132020131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 815894886361 + 494307424900 = 903269^2 + 703070^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310202311261 - 222 = 1310198116957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310202311461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655101155630 + 655101155631.
It is an arithmetic number, because the mean of its divisors is an integer number (655101155631).
Almost surely, 21310202311261 is an apocalyptic number.
It is an amenable number.
1310202311261 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310202311261 is an equidigital number, since it uses as much as digits as its factorization.
1310202311261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1310202311261 its reverse (1621132020131), we get a palindrome (2931334331392).
The spelling of 1310202311261 in words is "one trillion, three hundred ten billion, two hundred two million, three hundred eleven thousand, two hundred sixty-one".
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