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131020310 = 2513102031
BaseRepresentation
bin1111100111100…
…11011000010110
3100010112112002002
413303303120112
5232020122220
621000115302
73150440261
oct763633026
9303475062
10131020310
1167a59553
1237a65b32
13211b5015
1413587cd8
15b780c75
hex7cf3616

131020310 has 8 divisors (see below), whose sum is σ = 235836576. Its totient is φ = 52408120.

The previous prime is 131020301. The next prime is 131020369. The reversal of 131020310 is 13020131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1310203102 = 34332643264992200, which contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131020291 and 131020300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6551006 + ... + 6551025.

It is an arithmetic number, because the mean of its divisors is an integer number (29479572).

Almost surely, 2131020310 is an apocalyptic number.

131020310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131020310 is a deficient number, since it is larger than the sum of its proper divisors (104816266).

131020310 is a wasteful number, since it uses less digits than its factorization.

131020310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13102038.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 131020310 is about 11446.4103543425. The cubic root of 131020310 is about 507.9015531427.

Adding to 131020310 its reverse (13020131), we get a palindrome (144040441).

The spelling of 131020310 in words is "one hundred thirty-one million, twenty thousand, three hundred ten".

Divisors: 1 2 5 10 13102031 26204062 65510155 131020310