13102031033009 has 2 divisors, whose sum is σ = 13102031033010. Its totient is φ = 13102031033008.

The previous prime is 13102031032931. The next prime is 13102031033011. The reversal of 13102031033009 is 90033013020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13098268437409 + 3762595600 = 3619153^2 + 61340^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102031033009 is a prime.

Together with 13102031033011, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13102033033009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551015516504 + 6551015516505.

It is an arithmetic number, because the mean of its divisors is an integer number (6551015516505).

Almost surely, 2^{13102031033009} is an apocalyptic number.

It is an amenable number.

13102031033009 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102031033009 is an equidigital number, since it uses as much as digits as its factorization.

13102031033009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 26.

The spelling of 13102031033009 in words is "thirteen trillion, one hundred two billion, thirty-one million, thirty-three thousand, nine".