13102031301001 has 2 divisors, whose sum is σ = 13102031301002. Its totient is φ = 13102031301000.

The previous prime is 13102031300993. The next prime is 13102031301019. The reversal of 13102031301001 is 10010313020131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6949423902976 + 6152607398025 = 2636176^2 + 2480445^2 .

It is an emirp because it is prime and its reverse (10010313020131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13102031301001 - 2³ = 13102031300993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13102031301061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551015650500 + 6551015650501.

It is an arithmetic number, because the mean of its divisors is an integer number (6551015650501).

Almost surely, 2^{13102031301001} is an apocalyptic number.

It is an amenable number.

13102031301001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102031301001 is an equidigital number, since it uses as much as digits as its factorization.

13102031301001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13102031301001 its reverse (10010313020131), we get a palindrome (23112344321132).

The spelling of 13102031301001 in words is "thirteen trillion, one hundred two billion, thirty-one million, three hundred one thousand, one".