13102031301019 has 2 divisors, whose sum is σ = 13102031301020. Its totient is φ = 13102031301018.

The previous prime is 13102031301001. The next prime is 13102031301043. The reversal of 13102031301019 is 91010313020131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13102031301019 - 2⁵ = 13102031300987 is a prime.

It is a super-2 number, since 2×13102031301019² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13102031300984 and 13102031301002.

It is not a weakly prime, because it can be changed into another prime (13102031361019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551015650509 + 6551015650510.

It is an arithmetic number, because the mean of its divisors is an integer number (6551015650510).

Almost surely, 2^{13102031301019} is an apocalyptic number.

13102031301019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102031301019 is an equidigital number, since it uses as much as digits as its factorization.

13102031301019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 13102031301019 in words is "thirteen trillion, one hundred two billion, thirty-one million, three hundred one thousand, nineteen".