13102031301131 has 2 divisors, whose sum is σ = 13102031301132. Its totient is φ = 13102031301130.

The previous prime is 13102031301103. The next prime is 13102031301133. The reversal of 13102031301131 is 13110313020131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13102031301131 - 2²² = 13102027106827 is a prime.

It is a super-2 number, since 2×13102031301131² (a number of 27 digits) contains 22 as substring.

Together with 13102031301133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13102031301133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551015650565 + 6551015650566.

It is an arithmetic number, because the mean of its divisors is an integer number (6551015650566).

Almost surely, 2^{13102031301131} is an apocalyptic number.

13102031301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102031301131 is an equidigital number, since it uses as much as digits as its factorization.

13102031301131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 13102031301131 its reverse (13110313020131), we get a palindrome (26212344321262).

The spelling of 13102031301131 in words is "thirteen trillion, one hundred two billion, thirty-one million, three hundred one thousand, one hundred thirty-one".