Base | Representation |
---|---|
bin | 1011111010101000110111… |
… | …1110110100111111010111 |
3 | 1201101112122011021221001111 |
4 | 2332222031332310333113 |
5 | 3204130430232411411 |
6 | 43510553543035451 |
7 | 2521406401051534 |
oct | 276521576647727 |
9 | 51345564257044 |
10 | 13102032310231 |
11 | 41a15a4740627 |
12 | 157731813bb87 |
13 | 740693545897 |
14 | 3341dad51d8b |
15 | 17ac32017721 |
hex | bea8dfb4fd7 |
13102032310231 has 2 divisors, whose sum is σ = 13102032310232. Its totient is φ = 13102032310230.
The previous prime is 13102032310193. The next prime is 13102032310247. The reversal of 13102032310231 is 13201323020131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102032310231 - 233 = 13093442375639 is a prime.
It is a super-2 number, since 2×131020323102312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102032310531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551016155115 + 6551016155116.
It is an arithmetic number, because the mean of its divisors is an integer number (6551016155116).
Almost surely, 213102032310231 is an apocalyptic number.
13102032310231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102032310231 is an equidigital number, since it uses as much as digits as its factorization.
13102032310231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13102032310231 its reverse (13201323020131), we get a palindrome (26303355330362).
The spelling of 13102032310231 in words is "thirteen trillion, one hundred two billion, thirty-two million, three hundred ten thousand, two hundred thirty-one".
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