Base | Representation |
---|---|
bin | 1011111010101000111000… |
… | …0001100011000101010111 |
3 | 1201101112122012122011020011 |
4 | 2332222032001203011113 |
5 | 3204130430423221234 |
6 | 43510554010221051 |
7 | 2521406410111522 |
oct | 276521601430527 |
9 | 51345565564204 |
10 | 13102033023319 |
11 | 41a15a5088359 |
12 | 1577318424787 |
13 | 740693735326 |
14 | 3341db099bb9 |
15 | 17ac32108b64 |
hex | bea8e063157 |
13102033023319 has 2 divisors, whose sum is σ = 13102033023320. Its totient is φ = 13102033023318.
The previous prime is 13102033023257. The next prime is 13102033023349. The reversal of 13102033023319 is 91332033020131.
13102033023319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102033023319 - 211 = 13102033021271 is a prime.
It is a super-2 number, since 2×131020330233192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102033023349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551016511659 + 6551016511660.
It is an arithmetic number, because the mean of its divisors is an integer number (6551016511660).
Almost surely, 213102033023319 is an apocalyptic number.
13102033023319 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102033023319 is an equidigital number, since it uses as much as digits as its factorization.
13102033023319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 31.
The spelling of 13102033023319 in words is "thirteen trillion, one hundred two billion, thirty-three million, twenty-three thousand, three hundred nineteen".
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