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131020420134053 is a prime number
BaseRepresentation
bin11101110010100110010001…
…100110011011010010100101
3122011220102121100112000002002
4131302212101212123102211
5114133114310023242203
61142353541114455045
736411625102554152
oct3562462146332245
9564812540460062
10131020420134053
11388244a251a06a
1212840775734485
135815232299388
14244d5ca613229
15102321d8b9d88
hex77299199b4a5

131020420134053 has 2 divisors, whose sum is σ = 131020420134054. Its totient is φ = 131020420134052.

The previous prime is 131020420133923. The next prime is 131020420134167. The reversal of 131020420134053 is 350431024020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127729033182529 + 3291386951524 = 11301727^2 + 1814218^2 .

It is a cyclic number.

It is not a de Polignac number, because 131020420134053 - 220 = 131020419085477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020420134353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510210067026 + 65510210067027.

It is an arithmetic number, because the mean of its divisors is an integer number (65510210067027).

Almost surely, 2131020420134053 is an apocalyptic number.

It is an amenable number.

131020420134053 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020420134053 is an equidigital number, since it uses as much as digits as its factorization.

131020420134053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 131020420134053 its reverse (350431024020131), we get a palindrome (481451444154184).

The spelling of 131020420134053 in words is "one hundred thirty-one trillion, twenty billion, four hundred twenty million, one hundred thirty-four thousand, fifty-three".