Base | Representation |
---|---|
bin | 11101110010100110010010… |
… | …010001011110101010000010 |
3 | 122011220102122010202101112101 |
4 | 131302212102101132222002 |
5 | 114133114320420420114 |
6 | 1142353542200421014 |
7 | 36411625300520662 |
oct | 3562462221365202 |
9 | 564812563671471 |
10 | 131020431420034 |
11 | 388244a8928422 |
12 | 1284077947776a |
13 | 581523471b380 |
14 | 244d5cbd101a2 |
15 | 102321e898d74 |
hex | 77299245ea82 |
131020431420034 has 64 divisors (see below), whose sum is σ = 217913175849600. Its totient is φ = 58689394864128.
The previous prime is 131020431420013. The next prime is 131020431420097. The reversal of 131020431420034 is 430024134020131.
It is a happy number.
It is a super-2 number, since 2×1310204314200342 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131020431419984 and 131020431420011.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 645901794 + ... + 646104610.
It is an arithmetic number, because the mean of its divisors is an integer number (3404893372650).
Almost surely, 2131020431420034 is an apocalyptic number.
131020431420034 is a deficient number, since it is larger than the sum of its proper divisors (86892744429566).
131020431420034 is a wasteful number, since it uses less digits than its factorization.
131020431420034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204547.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131020431420034 its reverse (430024134020131), we get a palindrome (561044565440165).
The spelling of 131020431420034 in words is "one hundred thirty-one trillion, twenty billion, four hundred thirty-one million, four hundred twenty thousand, thirty-four".
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