Base | Representation |
---|---|
bin | 11000011001111001… |
… | …00011001011100111 |
3 | 1020211002220201000021 |
4 | 30030330203023213 |
5 | 203313114214343 |
6 | 10004035300011 |
7 | 642453010561 |
oct | 141474431347 |
9 | 36732821007 |
10 | 13102101223 |
11 | 5613881632 |
12 | 2657a4a607 |
13 | 130a59ca23 |
14 | 8c4146331 |
15 | 51a3be0ed |
hex | 30cf232e7 |
13102101223 has 2 divisors, whose sum is σ = 13102101224. Its totient is φ = 13102101222.
The previous prime is 13102101151. The next prime is 13102101253. The reversal of 13102101223 is 32210120131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102101223 - 213 = 13102093031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102101197 and 13102101206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102101253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551050611 + 6551050612.
It is an arithmetic number, because the mean of its divisors is an integer number (6551050612).
Almost surely, 213102101223 is an apocalyptic number.
13102101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102101223 is an equidigital number, since it uses as much as digits as its factorization.
13102101223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13102101223 its reverse (32210120131), we get a palindrome (45312221354).
The spelling of 13102101223 in words is "thirteen billion, one hundred two million, one hundred one thousand, two hundred twenty-three".
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