1310211130130 has 64 divisors (see below), whose sum is σ = 2813268976128. Its totient is φ = 429563312640.

The previous prime is 1310211130097. The next prime is 1310211130171. The reversal of 1310211130130 is 310311120131.

It is a junction number, because it is equal to n+sod(n) for n = 1310211130099 and 1310211130108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5704310 + ... + 5929550.

It is an arithmetic number, because the mean of its divisors is an integer number (43957327752).

Almost surely, 2^{1310211130130} is an apocalyptic number.

1310211130130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310211130130 is an abundant number, since it is smaller than the sum of its proper divisors (1503057845998).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310211130130 is a wasteful number, since it uses less digits than its factorization.

1310211130130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228891.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1310211130130 its reverse (310311120131), we get a palindrome (1620522250261).

Subtracting from 1310211130130 its reverse (310311120131), we obtain a palindrome (999900009999).

The spelling of 1310211130130 in words is "one trillion, three hundred ten billion, two hundred eleven million, one hundred thirty thousand, one hundred thirty".