Base | Representation |
---|---|
bin | 111101000000101110… |
… | …1111101000011110110 |
3 | 110112012002101010102100 |
4 | 1322001131331003312 |
5 | 4121312402211042 |
6 | 140105033322530 |
7 | 12315553150434 |
oct | 1720135750366 |
9 | 415162333370 |
10 | 131021132022 |
11 | 506250167a0 |
12 | 21486866446 |
13 | c480600471 |
14 | 64acd57d54 |
15 | 361c81b24c |
hex | 1e8177d0f6 |
131021132022 has 48 divisors (see below), whose sum is σ = 310169742480. Its totient is φ = 39641395200.
The previous prime is 131021131957. The next prime is 131021132029. The reversal of 131021132022 is 220231120131.
131021132022 is a `hidden beast` number, since 1 + 310 + 2 + 11 + 320 + 22 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 131021131986 and 131021132004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131021132029) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 389247 + ... + 643082.
It is an arithmetic number, because the mean of its divisors is an integer number (6461869635).
Almost surely, 2131021132022 is an apocalyptic number.
131021132022 is an abundant number, since it is smaller than the sum of its proper divisors (179148610458).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131021132022 is a wasteful number, since it uses less digits than its factorization.
131021132022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1032989 (or 1032986 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 131021132022 its reverse (220231120131), we get a palindrome (351252252153).
The spelling of 131021132022 in words is "one hundred thirty-one billion, twenty-one million, one hundred thirty-two thousand, twenty-two".
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