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131021143410427 is a prime number
BaseRepresentation
bin11101110010100110111100…
…101101100000011011111011
3122011220111110202111020201221
4131302212330231200123323
5114133122300203113202
61142354140553052511
736411652034401504
oct3562467455403373
9564814422436657
10131021143410427
1138824833817336
12128409379b7137
13581531909826a
14244d6586c9bab
151023262139037
hex7729bcb606fb

131021143410427 has 2 divisors, whose sum is σ = 131021143410428. Its totient is φ = 131021143410426.

The previous prime is 131021143410419. The next prime is 131021143410433. The reversal of 131021143410427 is 724014341120131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131021143410427 - 23 = 131021143410419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131021143410392 and 131021143410401.

It is not a weakly prime, because it can be changed into another prime (131021143410127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510571705213 + 65510571705214.

It is an arithmetic number, because the mean of its divisors is an integer number (65510571705214).

Almost surely, 2131021143410427 is an apocalyptic number.

131021143410427 is a deficient number, since it is larger than the sum of its proper divisors (1).

131021143410427 is an equidigital number, since it uses as much as digits as its factorization.

131021143410427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 131021143410427 its reverse (724014341120131), we get a palindrome (855035484530558).

The spelling of 131021143410427 in words is "one hundred thirty-one trillion, twenty-one billion, one hundred forty-three million, four hundred ten thousand, four hundred twenty-seven".