Base | Representation |
---|---|
bin | 11101110010100110111100… |
… | …101101100000011011111011 |
3 | 122011220111110202111020201221 |
4 | 131302212330231200123323 |
5 | 114133122300203113202 |
6 | 1142354140553052511 |
7 | 36411652034401504 |
oct | 3562467455403373 |
9 | 564814422436657 |
10 | 131021143410427 |
11 | 38824833817336 |
12 | 128409379b7137 |
13 | 581531909826a |
14 | 244d6586c9bab |
15 | 1023262139037 |
hex | 7729bcb606fb |
131021143410427 has 2 divisors, whose sum is σ = 131021143410428. Its totient is φ = 131021143410426.
The previous prime is 131021143410419. The next prime is 131021143410433. The reversal of 131021143410427 is 724014341120131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131021143410427 - 23 = 131021143410419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131021143410392 and 131021143410401.
It is not a weakly prime, because it can be changed into another prime (131021143410127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510571705213 + 65510571705214.
It is an arithmetic number, because the mean of its divisors is an integer number (65510571705214).
Almost surely, 2131021143410427 is an apocalyptic number.
131021143410427 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021143410427 is an equidigital number, since it uses as much as digits as its factorization.
131021143410427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 131021143410427 its reverse (724014341120131), we get a palindrome (855035484530558).
The spelling of 131021143410427 in words is "one hundred thirty-one trillion, twenty-one billion, one hundred forty-three million, four hundred ten thousand, four hundred twenty-seven".
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