13102122433 has 2 divisors, whose sum is σ = 13102122434. Its totient is φ = 13102122432.

The previous prime is 13102122409. The next prime is 13102122457. The reversal of 13102122433 is 33422120131.

It is a balanced prime because it is at equal distance from previous prime (13102122409) and next prime (13102122457).

It can be written as a sum of positive squares in only one way, i.e., 12992124289 + 109998144 = 113983^2 + 10488^2 .

It is a cyclic number.

It is not a de Polignac number, because 13102122433 - 2¹⁷ = 13101991361 is a prime.

It is a super-2 number, since 2×13102122433² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13102122463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551061216 + 6551061217.

It is an arithmetic number, because the mean of its divisors is an integer number (6551061217).

Almost surely, 2^13102122433 is an apocalyptic number.

It is an amenable number.

13102122433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102122433 is an equidigital number, since it uses as much as digits as its factorization.

13102122433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13102122433 its reverse (33422120131), we get a palindrome (46524242564).

The spelling of 13102122433 in words is "thirteen billion, one hundred two million, one hundred twenty-two thousand, four hundred thirty-three".