1310213144440 has 16 divisors (see below), whose sum is σ = 2947979575080. Its totient is φ = 524085257760.

The previous prime is 1310213144423. The next prime is 1310213144483. The reversal of 1310213144440 is 444413120131.

It is a junction number, because it is equal to n+sod(n) for n = 1310213144399 and 1310213144408.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16377664266 + ... + 16377664345.

Almost surely, 2^{1310213144440} is an apocalyptic number.

1310213144440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310213144440 is an abundant number, since it is smaller than the sum of its proper divisors (1637766430640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310213144440 is a wasteful number, since it uses less digits than its factorization.

1310213144440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32755328622 (or 32755328618 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1310213144440 its reverse (444413120131), we get a palindrome (1754626264571).

The spelling of 1310213144440 in words is "one trillion, three hundred ten billion, two hundred thirteen million, one hundred forty-four thousand, four hundred forty".