Base | Representation |
---|---|
bin | 10011000100001110110… |
… | …110100110100110011011 |
3 | 11122020220002012121012112 |
4 | 103010032312212212123 |
5 | 132431304320021222 |
6 | 2441523141502535 |
7 | 163442221055105 |
oct | 23041666464633 |
9 | 4566802177175 |
10 | 1310214220187 |
11 | 465727851a84 |
12 | 191b18111a4b |
13 | 967252aa602 |
14 | 475b3d52575 |
15 | 241359eabe2 |
hex | 1310eda699b |
1310214220187 has 2 divisors, whose sum is σ = 1310214220188. Its totient is φ = 1310214220186.
The previous prime is 1310214220171. The next prime is 1310214220243. The reversal of 1310214220187 is 7810224120131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310214220187 - 24 = 1310214220171 is a prime.
It is a super-2 number, since 2×13102142201872 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310214220487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655107110093 + 655107110094.
It is an arithmetic number, because the mean of its divisors is an integer number (655107110094).
Almost surely, 21310214220187 is an apocalyptic number.
1310214220187 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310214220187 is an equidigital number, since it uses as much as digits as its factorization.
1310214220187 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 32.
The spelling of 1310214220187 in words is "one trillion, three hundred ten billion, two hundred fourteen million, two hundred twenty thousand, one hundred eighty-seven".
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