Base | Representation |
---|---|
bin | 11101110010100111001101… |
… | …111111000001000010101111 |
3 | 122011220112012221210202021101 |
4 | 131302213031333001002233 |
5 | 114133123343400304403 |
6 | 1142354225424343531 |
7 | 36411662153600326 |
oct | 3562471577010257 |
9 | 564815187722241 |
10 | 131021433213103 |
11 | 38824972366384 |
12 | 128409b8a74ba7 |
13 | 5815364135734 |
14 | 244d684da70bd |
15 | 102327c7d171d |
hex | 7729cdfc10af |
131021433213103 has 2 divisors, whose sum is σ = 131021433213104. Its totient is φ = 131021433213102.
The previous prime is 131021433213059. The next prime is 131021433213113. The reversal of 131021433213103 is 301312334120131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131021433213103 - 221 = 131021431115951 is a prime.
It is a super-2 number, since 2×1310214332131032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131021433213113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510716606551 + 65510716606552.
It is an arithmetic number, because the mean of its divisors is an integer number (65510716606552).
Almost surely, 2131021433213103 is an apocalyptic number.
131021433213103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021433213103 is an equidigital number, since it uses as much as digits as its factorization.
131021433213103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 131021433213103 its reverse (301312334120131), we get a palindrome (432333767333234).
The spelling of 131021433213103 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred thirty-three million, two hundred thirteen thousand, one hundred three".
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