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131022001424401 is a prime number
BaseRepresentation
bin11101110010100111101111…
…110110100100100000010001
3122011220120200112222212122021
4131302213233312210200101
5114133131024331040101
61142354402043211441
736412012223401123
oct3562475766444021
9564816615885567
10131022001424401
113882513408199a
1212840b37216b81
135815424a81139
14244d6da637213
1510232b26205a1
hex7729efda4811

131022001424401 has 2 divisors, whose sum is σ = 131022001424402. Its totient is φ = 131022001424400.

The previous prime is 131022001424389. The next prime is 131022001424423. The reversal of 131022001424401 is 104424100220131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124526517131025 + 6495484293376 = 11159145^2 + 2548624^2 .

It is a cyclic number.

It is not a de Polignac number, because 131022001424401 - 219 = 131022000900113 is a prime.

It is not a weakly prime, because it can be changed into another prime (131022001424441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511000712200 + 65511000712201.

It is an arithmetic number, because the mean of its divisors is an integer number (65511000712201).

Almost surely, 2131022001424401 is an apocalyptic number.

It is an amenable number.

131022001424401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131022001424401 is an equidigital number, since it uses as much as digits as its factorization.

131022001424401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 131022001424401 its reverse (104424100220131), we get a palindrome (235446101644532).

The spelling of 131022001424401 in words is "one hundred thirty-one trillion, twenty-two billion, one million, four hundred twenty-four thousand, four hundred one".