Base | Representation |
---|---|
bin | 111101000000110000… |
… | …1101110010110000011 |
3 | 110112012011020100010002 |
4 | 1322001201232112003 |
5 | 4121313130322243 |
6 | 140105110430215 |
7 | 12315564434663 |
oct | 1720141562603 |
9 | 415164210102 |
10 | 131022120323 |
11 | 50625631276 |
12 | 2148706236b |
13 | c480888263 |
14 | 64ad1341a3 |
15 | 361c963eb8 |
hex | 1e8186e583 |
131022120323 has 2 divisors, whose sum is σ = 131022120324. Its totient is φ = 131022120322.
The previous prime is 131022120301. The next prime is 131022120343. The reversal of 131022120323 is 323021220131.
It is an a-pointer prime, because the next prime (131022120343) can be obtained adding 131022120323 to its sum of digits (20).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131022120323 - 28 = 131022120067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131022120295 and 131022120304.
It is not a weakly prime, because it can be changed into another prime (131022120343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511060161 + 65511060162.
It is an arithmetic number, because the mean of its divisors is an integer number (65511060162).
Almost surely, 2131022120323 is an apocalyptic number.
131022120323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022120323 is an equidigital number, since it uses as much as digits as its factorization.
131022120323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 131022120323 its reverse (323021220131), we get a palindrome (454043340454).
The spelling of 131022120323 in words is "one hundred thirty-one billion, twenty-two million, one hundred twenty thousand, three hundred twenty-three".
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