Base | Representation |
---|---|
bin | 11000011001111010… |
… | …00000001011101011 |
3 | 1020211010010201221211 |
4 | 30030331000023223 |
5 | 203313132020021 |
6 | 10004042013551 |
7 | 642454014106 |
oct | 141475001353 |
9 | 36733121854 |
10 | 13102220011 |
11 | 5613952901 |
12 | 2657aa72b7 |
13 | 130a611b0a |
14 | 8c417773d |
15 | 51a3e43e1 |
hex | 30cf402eb |
13102220011 has 2 divisors, whose sum is σ = 13102220012. Its totient is φ = 13102220010.
The previous prime is 13102220003. The next prime is 13102220017. The reversal of 13102220011 is 11002220131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102220011 - 23 = 13102220003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102219973 and 13102220000.
It is not a weakly prime, because it can be changed into another prime (13102220017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551110005 + 6551110006.
It is an arithmetic number, because the mean of its divisors is an integer number (6551110006).
Almost surely, 213102220011 is an apocalyptic number.
13102220011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102220011 is an equidigital number, since it uses as much as digits as its factorization.
13102220011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 13102220011 its reverse (11002220131), we get a palindrome (24104440142).
The spelling of 13102220011 in words is "thirteen billion, one hundred two million, two hundred twenty thousand, eleven".
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