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131022222001357 is a prime number
BaseRepresentation
bin11101110010100111111101…
…000000000000010011001101
3122011220121020221001100100011
4131302213331000000103031
5114133132002313020412
61142354440003033221
736412020542306461
oct3562477500002315
9564817227040304
10131022222001357
11388252376396a5
1212840b9906b811
13581545b69134b
14244d71ba544a1
1510232c6b917a7
hex7729fd0004cd

131022222001357 has 2 divisors, whose sum is σ = 131022222001358. Its totient is φ = 131022222001356.

The previous prime is 131022222001259. The next prime is 131022222001361. The reversal of 131022222001357 is 753100222220131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115695537266596 + 15326684734761 = 10756186^2 + 3914931^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131022222001357 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131022222001397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511111000678 + 65511111000679.

It is an arithmetic number, because the mean of its divisors is an integer number (65511111000679).

Almost surely, 2131022222001357 is an apocalyptic number.

It is an amenable number.

131022222001357 is a deficient number, since it is larger than the sum of its proper divisors (1).

131022222001357 is an equidigital number, since it uses as much as digits as its factorization.

131022222001357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 131022222001357 its reverse (753100222220131), we get a palindrome (884122444221488).

The spelling of 131022222001357 in words is "one hundred thirty-one trillion, twenty-two billion, two hundred twenty-two million, one thousand, three hundred fifty-seven".