Base | Representation |
---|---|
bin | 111101000000110001… |
… | …0011010100000100011 |
3 | 110112012011120112020221 |
4 | 1322001202122200203 |
5 | 4121313202114334 |
6 | 140105114343511 |
7 | 12315566120245 |
oct | 1720142324043 |
9 | 415164515227 |
10 | 131022301219 |
11 | 50625745177 |
12 | 2148712ab97 |
13 | c48091c6b4 |
14 | 64ad180095 |
15 | 361c99c8b4 |
hex | 1e8189a823 |
131022301219 has 2 divisors, whose sum is σ = 131022301220. Its totient is φ = 131022301218.
The previous prime is 131022301187. The next prime is 131022301253. The reversal of 131022301219 is 912103220131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131022301219 - 25 = 131022301187 is a prime.
It is a super-2 number, since 2×1310223012192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131022301193 and 131022301202.
It is not a weakly prime, because it can be changed into another prime (131022301279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511150609 + 65511150610.
It is an arithmetic number, because the mean of its divisors is an integer number (65511150610).
Almost surely, 2131022301219 is an apocalyptic number.
131022301219 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022301219 is an equidigital number, since it uses as much as digits as its factorization.
131022301219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 131022301219 in words is "one hundred thirty-one billion, twenty-two million, three hundred one thousand, two hundred nineteen".
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