Base | Representation |
---|---|
bin | 10011000100001111011… |
… | …101000011110100001000 |
3 | 11122020220210011202220211 |
4 | 103010033131003310020 |
5 | 132431314410120240 |
6 | 2441524141530504 |
7 | 163442402543134 |
oct | 23041735036410 |
9 | 4566823152824 |
10 | 1310224301320 |
11 | 4657325080a0 |
12 | 191b1b573a34 |
13 | 967273ca08c |
14 | 475b54183c4 |
15 | 2413683cbea |
hex | 1310f743d08 |
1310224301320 has 64 divisors (see below), whose sum is σ = 3216362515200. Its totient is φ = 476392250880.
The previous prime is 1310224301297. The next prime is 1310224301339. The reversal of 1310224301320 is 231034220131.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 1310224301291 and 1310224301300.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3912241 + ... + 4233919.
It is an arithmetic number, because the mean of its divisors is an integer number (50255664300).
Almost surely, 21310224301320 is an apocalyptic number.
1310224301320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310224301320 is an abundant number, since it is smaller than the sum of its proper divisors (1906138213880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310224301320 is a wasteful number, since it uses less digits than its factorization.
1310224301320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 330958 (or 330954 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 1310224301320 its reverse (231034220131), we get a palindrome (1541258521451).
The spelling of 1310224301320 in words is "one trillion, three hundred ten billion, two hundred twenty-four million, three hundred one thousand, three hundred twenty".
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