Base | Representation |
---|---|
bin | 111101000000110010… |
… | …1000100010101101111 |
3 | 110112012012212212110221 |
4 | 1322001211010111233 |
5 | 4121313341344342 |
6 | 140105141312211 |
7 | 12315605045311 |
oct | 1720145042557 |
9 | 415165785427 |
10 | 131022996847 |
11 | 5062607a876 |
12 | 21487405667 |
13 | c480b04202 |
14 | 64ad2c17b1 |
15 | 361ca88a67 |
hex | 1e8194456f |
131022996847 has 2 divisors, whose sum is σ = 131022996848. Its totient is φ = 131022996846.
The previous prime is 131022996763. The next prime is 131022996869. The reversal of 131022996847 is 748699220131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131022996847 - 211 = 131022994799 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131022996794 and 131022996803.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131022996047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511498423 + 65511498424.
It is an arithmetic number, because the mean of its divisors is an integer number (65511498424).
Almost surely, 2131022996847 is an apocalyptic number.
131022996847 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022996847 is an equidigital number, since it uses as much as digits as its factorization.
131022996847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 52.
The spelling of 131022996847 in words is "one hundred thirty-one billion, twenty-two million, nine hundred ninety-six thousand, eight hundred forty-seven".
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