Base | Representation |
---|---|
bin | 1011111010101001111000… |
… | …0000010010110110000111 |
3 | 1201101120022220010101121122 |
4 | 2332222132000102312013 |
5 | 3204132003042130434 |
6 | 43511040344504155 |
7 | 2521416144016145 |
oct | 276523600226607 |
9 | 51346286111548 |
10 | 13102301130119 |
11 | 41a1722458a23 |
12 | 157739217b05b |
13 | 7407071474c6 |
14 | 33422492a595 |
15 | 17ac4a917c2e |
hex | bea9e012d87 |
13102301130119 has 2 divisors, whose sum is σ = 13102301130120. Its totient is φ = 13102301130118.
The previous prime is 13102301130109. The next prime is 13102301130131. The reversal of 13102301130119 is 91103110320131.
13102301130119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13102301130119 - 216 = 13102301064583 is a prime.
It is a super-2 number, since 2×131023011301192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102301130109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551150565059 + 6551150565060.
It is an arithmetic number, because the mean of its divisors is an integer number (6551150565060).
Almost surely, 213102301130119 is an apocalyptic number.
13102301130119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102301130119 is an equidigital number, since it uses as much as digits as its factorization.
13102301130119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 26.
The spelling of 13102301130119 in words is "thirteen trillion, one hundred two billion, three hundred one million, one hundred thirty thousand, one hundred nineteen".
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