Base | Representation |
---|---|
bin | 11000011001111010… |
… | …10110101111100001 |
3 | 1020211010022102201021 |
4 | 30030331112233201 |
5 | 203313142444132 |
6 | 10004044005441 |
7 | 642454550365 |
oct | 141475265741 |
9 | 36733272637 |
10 | 13102312417 |
11 | 5613a06277 |
12 | 2657b30881 |
13 | 130a644bac |
14 | 8c419d2a5 |
15 | 51a411997 |
hex | 30cf56be1 |
13102312417 has 2 divisors, whose sum is σ = 13102312418. Its totient is φ = 13102312416.
The previous prime is 13102312351. The next prime is 13102312469. The reversal of 13102312417 is 71421320131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11176506961 + 1925805456 = 105719^2 + 43884^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102312417 - 215 = 13102279649 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102312391 and 13102312400.
It is not a weakly prime, because it can be changed into another prime (13102316417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551156208 + 6551156209.
It is an arithmetic number, because the mean of its divisors is an integer number (6551156209).
Almost surely, 213102312417 is an apocalyptic number.
It is an amenable number.
13102312417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102312417 is an equidigital number, since it uses as much as digits as its factorization.
13102312417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 13102312417 its reverse (71421320131), we get a palindrome (84523632548).
The spelling of 13102312417 in words is "thirteen billion, one hundred two million, three hundred twelve thousand, four hundred seventeen".
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