Search a number
-
+
13102314505535 = 54603569294569
BaseRepresentation
bin1011111010101001111011…
…0011010100010100111111
31201101120100211021221020102
42332222132303110110333
53204132020003134120
643511041543311315
72521416365504423
oct276523663242477
951346324257212
1013102314505535
1141a1729a64092
12157739674b53b
13740709b4b558
1433422660cb83
1517ac4bbaad75
hexbea9ecd453f

13102314505535 has 8 divisors (see below), whose sum is σ = 15726193201680. Its totient is φ = 10479574407744.

The previous prime is 13102314505487. The next prime is 13102314505549. The reversal of 13102314505535 is 53550541320131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13102314505535 - 220 = 13102313456959 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 284624270 + ... + 284670299.

It is an arithmetic number, because the mean of its divisors is an integer number (1965774150210).

Almost surely, 213102314505535 is an apocalyptic number.

13102314505535 is a deficient number, since it is larger than the sum of its proper divisors (2623878696145).

13102314505535 is an equidigital number, since it uses as much as digits as its factorization.

13102314505535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 569299177.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 13102314505535 its reverse (53550541320131), we get a palindrome (66652855825666).

The spelling of 13102314505535 in words is "thirteen trillion, one hundred two billion, three hundred fourteen million, five hundred five thousand, five hundred thirty-five".

Divisors: 1 5 4603 23015 569294569 2846472845 2620462901107 13102314505535