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53550541320131 is a prime number
BaseRepresentation
bin11000010110100001101001…
…11111100010111111000011
321000121101022022001100002002
430023100310333202333003
524004333002034221011
6305520440140014215
714164620222611252
oct1413206477427703
9230541268040062
1053550541320131
1116076725574119
12600a553b3136b
1323b5a4333211b
14d31c07cc4799
1562ce8c157c3b
hex30b434fe2fc3

53550541320131 has 2 divisors, whose sum is σ = 53550541320132. Its totient is φ = 53550541320130.

The previous prime is 53550541320109. The next prime is 53550541320167. The reversal of 53550541320131 is 13102314505535.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53550541320131 is a prime.

It is a super-2 number, since 2×535505413201312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53550541320631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26775270660065 + 26775270660066.

It is an arithmetic number, because the mean of its divisors is an integer number (26775270660066).

Almost surely, 253550541320131 is an apocalyptic number.

53550541320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

53550541320131 is an equidigital number, since it uses as much as digits as its factorization.

53550541320131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 53550541320131 its reverse (13102314505535), we get a palindrome (66652855825666).

The spelling of 53550541320131 in words is "fifty-three trillion, five hundred fifty billion, five hundred forty-one million, three hundred twenty thousand, one hundred thirty-one".