Base | Representation |
---|---|
bin | 11000010110100001101001… |
… | …11111100010111111000011 |
3 | 21000121101022022001100002002 |
4 | 30023100310333202333003 |
5 | 24004333002034221011 |
6 | 305520440140014215 |
7 | 14164620222611252 |
oct | 1413206477427703 |
9 | 230541268040062 |
10 | 53550541320131 |
11 | 16076725574119 |
12 | 600a553b3136b |
13 | 23b5a4333211b |
14 | d31c07cc4799 |
15 | 62ce8c157c3b |
hex | 30b434fe2fc3 |
53550541320131 has 2 divisors, whose sum is σ = 53550541320132. Its totient is φ = 53550541320130.
The previous prime is 53550541320109. The next prime is 53550541320167. The reversal of 53550541320131 is 13102314505535.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53550541320131 is a prime.
It is a super-2 number, since 2×535505413201312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53550541320631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26775270660065 + 26775270660066.
It is an arithmetic number, because the mean of its divisors is an integer number (26775270660066).
Almost surely, 253550541320131 is an apocalyptic number.
53550541320131 is a deficient number, since it is larger than the sum of its proper divisors (1).
53550541320131 is an equidigital number, since it uses as much as digits as its factorization.
53550541320131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 53550541320131 its reverse (13102314505535), we get a palindrome (66652855825666).
The spelling of 53550541320131 in words is "fifty-three trillion, five hundred fifty billion, five hundred forty-one million, three hundred twenty thousand, one hundred thirty-one".
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