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13102331300543 is a prime number
BaseRepresentation
bin1011111010101001111111…
…0011011000101010111111
31201101120101222220012122202
42332222133303120222333
53204132033303104133
643511043343302115
72521416661324442
oct276523763305277
951346358805582
1013102331300543
1141a1738495461
1215773a02aa93b
1374071047bc24
14334228941659
1517ac4d3c72e8
hexbea9fcd8abf

13102331300543 has 2 divisors, whose sum is σ = 13102331300544. Its totient is φ = 13102331300542.

The previous prime is 13102331300533. The next prime is 13102331300599. The reversal of 13102331300543 is 34500313320131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13102331300543 - 212 = 13102331296447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102331300533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551165650271 + 6551165650272.

It is an arithmetic number, because the mean of its divisors is an integer number (6551165650272).

Almost surely, 213102331300543 is an apocalyptic number.

13102331300543 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102331300543 is an equidigital number, since it uses as much as digits as its factorization.

13102331300543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 13102331300543 its reverse (34500313320131), we get a palindrome (47602644620674).

The spelling of 13102331300543 in words is "thirteen trillion, one hundred two billion, three hundred thirty-one million, three hundred thousand, five hundred forty-three".