1310233244011 has 2 divisors, whose sum is σ = 1310233244012. Its totient is φ = 1310233244010.

The previous prime is 1310233243967. The next prime is 1310233244051. The reversal of 1310233244011 is 1104423320131.

It is a strong prime.

It is an emirp because it is prime and its reverse (1104423320131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310233244011 - 2¹³ = 1310233235819 is a prime.

It is a super-2 number, since 2×1310233244011² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310233244051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655116622005 + 655116622006.

It is an arithmetic number, because the mean of its divisors is an integer number (655116622006).

Almost surely, 2^{1310233244011} is an apocalyptic number.

1310233244011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310233244011 is an equidigital number, since it uses as much as digits as its factorization.

1310233244011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1310233244011 its reverse (1104423320131), we get a palindrome (2414656564142).

The spelling of 1310233244011 in words is "one trillion, three hundred ten billion, two hundred thirty-three million, two hundred forty-four thousand, eleven".