Base | Representation |
---|---|
bin | 111101000000110011… |
… | …0101010010011100110 |
3 | 110112012020200002101122 |
4 | 1322001212222103212 |
5 | 4121313443231002 |
6 | 140105154253542 |
7 | 12315611435051 |
oct | 1720146522346 |
9 | 415166602348 |
10 | 131023414502 |
11 | 50626335642 |
12 | 214875872b2 |
13 | c480c1c346 |
14 | 64ad38da98 |
15 | 361cb1c6a2 |
hex | 1e819aa4e6 |
131023414502 has 4 divisors (see below), whose sum is σ = 196535121756. Its totient is φ = 65511707250.
The previous prime is 131023414499. The next prime is 131023414519. The reversal of 131023414502 is 205414320131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32755853624 + ... + 32755853627.
It is an arithmetic number, because the mean of its divisors is an integer number (49133780439).
Almost surely, 2131023414502 is an apocalyptic number.
131023414502 is a deficient number, since it is larger than the sum of its proper divisors (65511707254).
131023414502 is an equidigital number, since it uses as much as digits as its factorization.
131023414502 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65511707253.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 131023414502 its reverse (205414320131), we get a palindrome (336437734633).
The spelling of 131023414502 in words is "one hundred thirty-one billion, twenty-three million, four hundred fourteen thousand, five hundred two".
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