Base | Representation |
---|---|
bin | 111101000000110011… |
… | …1000010011000101100 |
3 | 110112012020212002200121 |
4 | 1322001213002120230 |
5 | 4121314004410012 |
6 | 140105200334324 |
7 | 12315612325441 |
oct | 1720147023054 |
9 | 415166762617 |
10 | 131023513132 |
11 | 506263a2756 |
12 | 214876143a4 |
13 | c480c551c5 |
14 | 64ad3b79c8 |
15 | 361cb3ba07 |
hex | 1e819c262c |
131023513132 has 24 divisors (see below), whose sum is σ = 239276975616. Its totient is φ = 62659059408.
The previous prime is 131023513123. The next prime is 131023513151. The reversal of 131023513132 is 231315320131.
131023513132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 131023513097 and 131023513106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1563933 + ... + 1645579.
It is an arithmetic number, because the mean of its divisors is an integer number (9969873984).
Almost surely, 2131023513132 is an apocalyptic number.
It is an amenable number.
131023513132 is a deficient number, since it is larger than the sum of its proper divisors (108253462484).
131023513132 is a wasteful number, since it uses less digits than its factorization.
131023513132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99117 (or 99115 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 131023513132 its reverse (231315320131), we get a palindrome (362338833263).
The spelling of 131023513132 in words is "one hundred thirty-one billion, twenty-three million, five hundred thirteen thousand, one hundred thirty-two".
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