131024004032232 has 24 divisors (see below), whose sum is σ = 354856677587490. Its totient is φ = 43674668010720.

The previous prime is 131024004032213. The next prime is 131024004032249. The reversal of 131024004032232 is 232230400420131.

131024004032232 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 24 + 0 + 0 + 403 + 2 + 232 = 666.

It can be written as a sum of positive squares in only one way, i.e., 80689150805796 + 50334853226436 = 8982714^2 + 7094706^2 .

It is a tau number, because it is divible by the number of its divisors (24).

It is a junction number, because it is equal to n+sod(n) for n = 131024004032196 and 131024004032205.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 909888916819 + ... + 909888916962.

Almost surely, 2^{131024004032232} is an apocalyptic number.

131024004032232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131024004032232 is an abundant number, since it is smaller than the sum of its proper divisors (223832673555258).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131024004032232 is a wasteful number, since it uses less digits than its factorization.

131024004032232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1819777833793 (or 1819777833786 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 131024004032232 its reverse (232230400420131), we get a palindrome (363254404452363).

The spelling of 131024004032232 in words is "one hundred thirty-one trillion, twenty-four billion, four million, thirty-two thousand, two hundred thirty-two".