Base | Representation |
---|---|
bin | 10011000100010000011… |
… | …001011111100001011011 |
3 | 11122020221212222122020102 |
4 | 103010100121133201123 |
5 | 132431332434042301 |
6 | 2441525505250015 |
7 | 163442654314121 |
oct | 23042031374133 |
9 | 4566855878212 |
10 | 1310240143451 |
11 | 465740448568 |
12 | 191b2493390b |
13 | 9672a785b15 |
14 | 475b757d911 |
15 | 24137e1bb6b |
hex | 1311065f85b |
1310240143451 has 2 divisors, whose sum is σ = 1310240143452. Its totient is φ = 1310240143450.
The previous prime is 1310240143447. The next prime is 1310240143501. The reversal of 1310240143451 is 1543410420131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310240143451 - 22 = 1310240143447 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310240143651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120071725 + 655120071726.
It is an arithmetic number, because the mean of its divisors is an integer number (655120071726).
Almost surely, 21310240143451 is an apocalyptic number.
1310240143451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310240143451 is an equidigital number, since it uses as much as digits as its factorization.
1310240143451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1310240143451 its reverse (1543410420131), we get a palindrome (2853650563582).
The spelling of 1310240143451 in words is "one trillion, three hundred ten billion, two hundred forty million, one hundred forty-three thousand, four hundred fifty-one".
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