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1310240143501 is a prime number
BaseRepresentation
bin10011000100010000011…
…001011111100010001101
311122020221212222122022021
4103010100121133202031
5132431332434043001
62441525505250141
7163442654314222
oct23042031374215
94566855878267
101310240143501
11465740448603
12191b24933951
139672a785b53
14475b757d949
1524137e1bba1
hex1311065f88d

1310240143501 has 2 divisors, whose sum is σ = 1310240143502. Its totient is φ = 1310240143500.

The previous prime is 1310240143451. The next prime is 1310240143519. The reversal of 1310240143501 is 1053410420131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1003823648100 + 306416495401 = 1001910^2 + 553549^2 .

It is an emirp because it is prime and its reverse (1053410420131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310240143501 - 211 = 1310240141453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310240143571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120071750 + 655120071751.

It is an arithmetic number, because the mean of its divisors is an integer number (655120071751).

Almost surely, 21310240143501 is an apocalyptic number.

It is an amenable number.

1310240143501 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310240143501 is an equidigital number, since it uses as much as digits as its factorization.

1310240143501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1310240143501 its reverse (1053410420131), we get a palindrome (2363650563632).

The spelling of 1310240143501 in words is "one trillion, three hundred ten billion, two hundred forty million, one hundred forty-three thousand, five hundred one".