13102443331 has 2 divisors, whose sum is σ = 13102443332. Its totient is φ = 13102443330.

The previous prime is 13102443323. The next prime is 13102443359. The reversal of 13102443331 is 13334420131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13102443331 - 2³ = 13102443323 is a prime.

It is a super-2 number, since 2×13102443331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13102443296 and 13102443305.

It is not a weakly prime, because it can be changed into another prime (13102443311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551221665 + 6551221666.

It is an arithmetic number, because the mean of its divisors is an integer number (6551221666).

Almost surely, 2^13102443331 is an apocalyptic number.

13102443331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102443331 is an equidigital number, since it uses as much as digits as its factorization.

13102443331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13102443331 its reverse (13334420131), we get a palindrome (26436863462).

The spelling of 13102443331 in words is "thirteen billion, one hundred two million, four hundred forty-three thousand, three hundred thirty-one".