Base | Representation |
---|---|
bin | 11000011001111100… |
… | …01110101010111111 |
3 | 1020211010202001221221 |
4 | 30030332032222333 |
5 | 203313222312003 |
6 | 10004052534211 |
7 | 642456523312 |
oct | 141476165277 |
9 | 36733661857 |
10 | 13102541503 |
11 | 56140523a7 |
12 | 2658021367 |
13 | 130a6c524c |
14 | 8c421c979 |
15 | 51a4597bd |
hex | 30cf8eabf |
13102541503 has 4 divisors (see below), whose sum is σ = 13422115728. Its totient is φ = 12782967280.
The previous prime is 13102541479. The next prime is 13102541509. The reversal of 13102541503 is 30514520131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30514520131 = 103 ⋅296257477.
It is a cyclic number.
It is not a de Polignac number, because 13102541503 - 229 = 12565670591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102541509) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159787051 + ... + 159787132.
It is an arithmetic number, because the mean of its divisors is an integer number (3355528932).
Almost surely, 213102541503 is an apocalyptic number.
13102541503 is a deficient number, since it is larger than the sum of its proper divisors (319574225).
13102541503 is an equidigital number, since it uses as much as digits as its factorization.
13102541503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 319574224.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 13102541503 in words is "thirteen billion, one hundred two million, five hundred forty-one thousand, five hundred three".
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