Base | Representation |
---|---|
bin | 1011111010101011011111… |
… | …1110010011110001100011 |
3 | 1201101121110020221121000002 |
4 | 2332222313332103301203 |
5 | 3204133401111123001 |
6 | 43511151511050215 |
7 | 2521433014214054 |
oct | 276526776236143 |
9 | 51347406847002 |
10 | 13102736817251 |
11 | 41a1926389134 |
12 | 157749407096b |
13 | 7407764a2543 |
14 | 33426674072b |
15 | 17ac73cca46b |
hex | beab7f93c63 |
13102736817251 has 2 divisors, whose sum is σ = 13102736817252. Its totient is φ = 13102736817250.
The previous prime is 13102736817239. The next prime is 13102736817257. The reversal of 13102736817251 is 15271863720131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13102736817251 - 210 = 13102736816227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102736817196 and 13102736817205.
It is not a weakly prime, because it can be changed into another prime (13102736817257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551368408625 + 6551368408626.
It is an arithmetic number, because the mean of its divisors is an integer number (6551368408626).
Almost surely, 213102736817251 is an apocalyptic number.
13102736817251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102736817251 is an equidigital number, since it uses as much as digits as its factorization.
13102736817251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 423360, while the sum is 47.
The spelling of 13102736817251 in words is "thirteen trillion, one hundred two billion, seven hundred thirty-six million, eight hundred seventeen thousand, two hundred fifty-one".
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